(ab bc ca)^3 formula 186417-(ab+bc+ca)^3 formula

Proof Formula \((abc)^3 = \\a^3 b^3 c^3 6abc \\ 3ab (ab) 3ac (ac) 3bc (bc) \) Summary (abc)^3 If you have any issues in the (abc)^3 formulas, please let me know

(ab+bc+ca)^3 formula-If a b c = 3√3 and a 2 b 2 c 2 = 9 then ab bc ca =? I simplified this equation too $$(ab)^3(bc)^3(ca)^3=abc(a^3b^3c^3)$$ I tried to subtract $3(abc)^2$ from both sides and it gave a factorised form

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How this identity of a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) is obtained Taking RHS of the identity (a b c)(a 2 b 2 c 2 ab bc ca ) Multiply each term of firstSolution To find (a b c) 2 Given that a = 2, b = 4, c = 3 Using the (a b c) 2 formula, (a b c) 2 = a 2 b 2 c 2 2ab 2bc 2ca (a b c) 2 = 2 2 4 2 3 2 2 (2) (4) 2 (4) (3) 2 (3)

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